What is (3x^3+3x^2-4x+5)+(x^3-2x^2+x-4) ?

The solution to (3x^3+3x^2-4x+5)+(x^3-2x^2+x-4) is 4x^3+x^2-3x+1

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simplify (3x^3+3x^2-4x+5)+(x^3-2x^2+x-4)

simplify

(3 x^{3} + 3 x^{2} - 4 x + 5) + (x^{3} - 2 x^{2} + x - 4)

4 x^{3} + x^{2} - 3 x + 1

Solution steps

(3 x^{3} + 3 x^{2} - 4 x + 5) + (x^{3} - 2 x^{2} + x - 4)

Simplify

(3 x^{3} + 3 x^{2} - 4 x + 5) + (x^{3} - 2 x^{2} + x - 4) : 3 x^{3} + 3 x^{2} - 4 x + 5 + x^{3} - 2 x^{2} + x - 4

= 3 x^{3} + 3 x^{2} - 4 x + 5 + x^{3} - 2 x^{2} + x - 4

Group like terms

= 3 x^{3} + x^{3} + 3 x^{2} - 2 x^{2} - 4 x + x + 5 - 4

Add similar elements:

3 x^{3} + x^{3} = 4 x^{3}

= 4 x^{3} + 3 x^{2} - 2 x^{2} - 4 x + x + 5 - 4

Add similar elements:

3 x^{2} - 2 x^{2} = x^{2}

= 4 x^{3} + x^{2} - 4 x + x + 5 - 4

Add similar elements:

- 4 x + x = - 3 x

= 4 x^{3} + x^{2} - 3 x + 5 - 4

Subtract the numbers:

5 - 4 = 1

= 4 x^{3} + x^{2} - 3 x + 1

(1 0^{3})^{2}

- lo g_{10} (0.03)

- 1 + \frac{5}{2}

(2 x + 3) (x - 5)

(3 - x)^{4}

What is (3x^3+3x^2-4x+5)+(x^3-2x^2+x-4) ?
The solution to (3x^3+3x^2-4x+5)+(x^3-2x^2+x-4) is 4x^3+x^2-3x+1