What are the solutions to the equation (x/9)^2-(2x)/3+1=0 ?

The solutions to the equation (x/9)^2-(2x)/3+1=0 are x=9(3+2sqrt(2)),x=9(3-2sqrt(2))

Find the zeros of (x/9)^2-(2x)/3+1=0

The zeros of (x/9)^2-(2x)/3+1=0 are x=9(3+2sqrt(2)),x=9(3-2sqrt(2))

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(\frac{x}{9})^{2} - \frac{2 x}{3} + 1 = 0

x = 9 (3 + 22), x = 9 (3 - 22)

Solution steps

(\frac{x}{9})^{2} - \frac{2 x}{3} + 1 = 0

Multiply both sides by

3

\frac{1 \cdot x ^{2}}{27} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot \frac{1}{27} \cdot 3}{2 \cdot \frac{1}{27}}

(- 2)^{2} - 4 \cdot \frac{1}{27} \cdot 3 = \frac{4 2}{3}

x_{1, 2} = \frac{- ( - 2 ) \pm \frac{4 2}{3}}{2 \cdot \frac{1}{27}}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + \frac{4 2}{3}}{2 \cdot \frac{1}{27}}, x_{2} = \frac{- ( - 2 ) - \frac{4 2}{3}}{2 \cdot \frac{1}{27}}

x = \frac{- ( - 2 ) + \frac{4 2}{3}}{2 \frac{1}{27}} : 9 (3 + 22)

x = \frac{- ( - 2 ) - \frac{4 2}{3}}{2 \frac{1}{27}} : 9 (3 - 22)

The solutions to the quadratic equation are:

x = 9 (3 + 22), x = 9 (3 - 22)

6 x + 8 = 3 x + 6

ln (0. 3^{14})

(\frac{1}{4})^{- 4}

3 x^{2} + 17 x - 6 < 0

8 m^{2} + 4 m

What are the solutions to the equation (x/9)^2-(2x)/3+1=0 ?
The solutions to the equation (x/9)^2-(2x)/3+1=0 are x=9(3+2sqrt(2)),x=9(3-2sqrt(2))
Find the zeros of (x/9)^2-(2x)/3+1=0
The zeros of (x/9)^2-(2x)/3+1=0 are x=9(3+2sqrt(2)),x=9(3-2sqrt(2))