What is factor 6x^3-7x^2-29x-12 ?

The solution to factor 6x^3-7x^2-29x-12 is (2x+1)(3x+4)(x-3)

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factor 6x^3-7x^2-29x-12

factor

6 x^{3} - 7 x^{2} - 29 x - 12

(2 x + 1) (3 x + 4) (x - 3)

Solution steps

6 x^{3} - 7 x^{2} - 29 x - 12

Use the rational root theorem

= (2 x + 1) \frac{6 x ^{3} - 7 x ^{2} - 29 x - 12}{2 x + 1}

\frac{6 x ^{3} - 7 x ^{2} - 29 x - 12}{2 x + 1} = 3 x^{2} - 5 x - 12

= (2 x + 1) (3 x^{2} - 5 x - 12)

Factor

3 x^{2} - 5 x - 12 : (3 x + 4) (x - 3)

= (2 x + 1) (3 x + 4) (x - 3)

\frac{( x ^{3} + y ^{3} )}{( x - y )}

- 3 \frac{1}{2}

\frac{x + \frac{x}{2}}{x - \frac{x}{4}}

\frac{6}{45}

y (y - 6) + 9 (y - 6)

What is factor 6x^3-7x^2-29x-12 ?
The solution to factor 6x^3-7x^2-29x-12 is (2x+1)(3x+4)(x-3)