What is (3+2i)/(1-2i) ?

The solution to (3+2i)/(1-2i) is -1/5+8/5 i

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simplify (3+2i)/(1-2i)

simplify

\frac{3 + 2 i}{1 - 2 i}

- \frac{1}{5} + \frac{8}{5} i

Solution steps

\frac{3 + 2 i}{1 - 2 i}

Multiply by the conjugate

\frac{1 + 2 i}{1 + 2 i}

= \frac{( 3 + 2 i ) ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )}

Simplify

\frac{( 3 + 2 i ) ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )} : \frac{- 1 + 8 i}{5}

= \frac{- 1 + 8 i}{5}

Rewrite in standard complex form:

- \frac{1}{5} + \frac{8}{5} i

= - \frac{1}{5} + \frac{8}{5} i

\frac{1}{sin ^{2} ( x )} + \frac{1}{cos ^{2} ( x )}

(2 x - 5) (3 x + 2)

(2 x + 4 y)^{2}

lo g_{10} (x^{4})

x^{4} - 3 x^{3}