What is 17*(a^{2n+1})^4*2a^{7n-12} ?

The solution to 17*(a^{2n+1})^4*2a^{7n-12} is 34a^{15n-8}

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simplify 17(a^{2n+1})^42a^{7n-12}

simplify

17 \cdot (a^{2 n + 1})^{4} \cdot 2 a^{7 n - 12}

34 a^{15 n - 8}

Solution steps

17 (a^{2 n + 1})^{4} \cdot 2 a^{7 n - 12}

Multiply the numbers:

17 \cdot 2 = 34

= 34 (a^{2 n + 1})^{4} a^{7 n - 12}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

(a^{2 n + 1})^{4} = a^{(2 n + 1) \cdot 4}

= 34 a^{(2 n + 1) \cdot 4} a^{7 n - 12}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a^{(2 n + 1) \cdot 4} a^{7 n - 12} = a^{(2 n + 1) \cdot 4 + 7 n - 12}

= 34 a^{(2 n + 1) \cdot 4 + 7 n - 12}

Simplify

(2 n + 1) \cdot 4 + 7 n - 12 : 15 n - 8

= 34 a^{15 n - 8}

(x - 3 x^{2})^{2} < (1 - 3 x)^{2}

\frac{2 x + 3}{15 - 5 x} \geq 0

- 5 u^{2} + 13 u - 6

\frac{x ^{3} y ^{4} x ^{- 2} y ^{- 5}}{y ^{3} x ^{5} y ^{- 2}}

5 (x^{2} - 1) > 24 x

What is 17*(a^{2n+1})^4*2a^{7n-12} ?
The solution to 17*(a^{2n+1})^4*2a^{7n-12} is 34a^{15n-8}