What is (\frac{x^3)/(x^2)}{(x^2-7x-8)/(x^2-1)} ?

The solution to (\frac{x^3)/(x^2)}{(x^2-7x-8)/(x^2-1)} is (x(x-1))/(x-8)

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simplify (\frac{x^3)/(x^2)}{(x^2-7x-8)/(x^2-1)}

simplify

\frac{\frac{x ^{3}}{x ^{2}}}{\frac{x ^{2} - 7 x - 8}{x ^{2} - 1}}

\frac{x ( x - 1 )}{x - 8}

Solution steps

\frac{\frac{x ^{3}}{x ^{2}}}{\frac{x ^{2} - 7 x - 8}{x ^{2} - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{x ^{3} ( x ^{2} - 1 )}{x ^{2} ( x ^{2} - 7 x - 8 )}

Cancel

\frac{x ^{3} ( x ^{2} - 1 )}{x ^{2} ( x ^{2} - 7 x - 8 )} : \frac{x ( x - 1 )}{x - 8}

= \frac{x ( x - 1 )}{x - 8}

(3 a^{2} b + 2 a) (3 a^{2} b - 2 a)

\frac{20}{3}

(5 x + 8)^{2}

f (x^{2})

- 81 x^{6}

What is (\frac{x^3)/(x^2)}{(x^2-7x-8)/(x^2-1)} ?
The solution to (\frac{x^3)/(x^2)}{(x^2-7x-8)/(x^2-1)} is (x(x-1))/(x-8)