What is (x^2-5x-24)/(6x+2x^2)*(5x^2)/(8-x) ?

The solution to (x^2-5x-24)/(6x+2x^2)*(5x^2)/(8-x) is -(5x)/2

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simplify (x^2-5x-24)/(6x+2x^2)*(5x^2)/(8-x)

simplify

\frac{x ^{2} - 5 x - 24}{6 x + 2 x ^{2}} \cdot \frac{5 x ^{2}}{8 - x}

- \frac{5 x}{2}

Solution steps

\frac{x ^{2} - 5 x - 24}{6 x + 2 x ^{2}} \cdot \frac{5 x ^{2}}{8 - x}

Cancel

\frac{x ^{2} - 5 x - 24}{6 x + 2 x ^{2}} : \frac{x - 8}{2 x}

= \frac{x - 8}{2 x} \cdot \frac{5 x ^{2}}{8 - x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x - 8 ) \cdot 5 x ^{2}}{2 x ( 8 - x )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{( x - 8 ) \cdot 5 xx}{2 x ( 8 - x )}

Cancel the common factor:

x

= \frac{( x - 8 ) \cdot 5 x}{2 ( 8 - x )}

2 (8 - x) = - 2 (x - 8)

= \frac{( x - 8 ) \cdot 5 x}{- 2 ( x - 8 )}

Cancel the common factor:

x - 8

= \frac{5 x}{- 2}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{5 x}{2}

(9 + 3 i)^{2}

(9^{3})^{2}

\frac{( x ^{8} + 2 x ^{7} - 3 x ^{6} + 2 x ^{5} - x ^{4} )}{( x ^{4} )}

\frac{7 - y}{y - 7}

\frac{x ^{2} - 25}{5 - x}

What is (x^2-5x-24)/(6x+2x^2)*(5x^2)/(8-x) ?
The solution to (x^2-5x-24)/(6x+2x^2)*(5x^2)/(8-x) is -(5x)/2