What is (3y^2z^3)^3(z^3y^4)^{-2} ?

The solution to (3y^2z^3)^3(z^3y^4)^{-2} is (27z^3)/(y^2)

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simplify (3y^2z^3)^3(z^3y^4)^{-2}

simplify

(3 y^{2} z^{3})^{3} (z^{3} y^{4})^{- 2}

\frac{27 z ^{3}}{y ^{2}}

Solution steps

(3 y^{2} z^{3})^{3} (z^{3} y^{4})^{- 2}

Simplify

(3 y^{2} z^{3})^{3} : 27 y^{6} z^{9}

= 27 y^{6} z^{9} (z^{3} y^{4})^{- 2}

Simplify

(z^{3} y^{4})^{- 2} : \frac{1}{z ^{6} y ^{8}}

= 27 y^{6} z^{9} \frac{1}{z ^{6} y ^{8}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{27 y ^{6} z ^{9} \cdot 1}{z ^{6} y ^{8}}

Multiply the numbers:

27 \cdot 1 = 27

= \frac{27 y ^{6} z ^{9}}{z ^{6} y ^{8}}

Simplify

\frac{z ^{9}}{z ^{6}} : z^{3}

= \frac{27 y ^{6} z ^{3}}{y ^{8}}

Simplify

\frac{y ^{6}}{y ^{8}} : \frac{1}{y ^{2}}

= \frac{27 z ^{3}}{y ^{2}}

lo g_{10} (3.5)

\frac{x - 9}{x - 3}

\frac{x ^{2} - 9}{x ^{2} + 6 x + 9} \cdot \frac{3 x + 9}{3 x - 9}

lo g_{3} (3 \frac{1}{2})

a + a + a + a

What is (3y^2z^3)^3(z^3y^4)^{-2} ?
The solution to (3y^2z^3)^3(z^3y^4)^{-2} is (27z^3)/(y^2)