What are the solutions to the equation 3x^2+4x=-3 ?

The solutions to the equation 3x^2+4x=-3 are x=-2/3+i(sqrt(5))/3 ,x=-2/3-i(sqrt(5))/3

Find the zeros of 3x^2+4x=-3

The zeros of 3x^2+4x=-3 are x=-2/3+i(sqrt(5))/3 ,x=-2/3-i(sqrt(5))/3

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3 x^{2} + 4 x = - 3

x = - \frac{2}{3} + i \frac{5}{3}, x = - \frac{2}{3} - i \frac{5}{3}

Solution steps

3 x^{2} + 4 x = - 3

Move

3

to the left side

3 x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 3 : 25 i

x_{1, 2} = \frac{- 4 \pm 2 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 5 i}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 5 i}{2 \cdot 3}

x = \frac{- 4 + 2 5 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{5}{3}

x = \frac{- 4 - 2 5 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} + i \frac{5}{3}, x = - \frac{2}{3} - i \frac{5}{3}

\frac{3}{2} + 1

3 x + 2 = 5

10 x^{2} - 17 x - 6 = 0

(e + 3) (e - 5)

m^{2} - 28 m + 196

What are the solutions to the equation 3x^2+4x=-3 ?
The solutions to the equation 3x^2+4x=-3 are x=-2/3+i(sqrt(5))/3 ,x=-2/3-i(sqrt(5))/3
Find the zeros of 3x^2+4x=-3
The zeros of 3x^2+4x=-3 are x=-2/3+i(sqrt(5))/3 ,x=-2/3-i(sqrt(5))/3