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Popular >

simplify ((1-i)/(-1+i))^{-1}

Solution

simplify

(\frac{1 - i}{- 1 + i})^{- 1}

Solution

- 1

Solution steps

(\frac{1 - i}{- 1 + i})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{1 - i}{- 1 + i})^{- 1} = \frac{1}{\frac{1 - i}{- 1 + i}}

= \frac{1}{\frac{1 - i}{- 1 + i}}

\frac{1}{\frac{1 - i}{- 1 + i}} = - 1

= - 1

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Frequently Asked Questions (FAQ)

What is ((1-i)/(-1+i))^{-1} ?
The solution to ((1-i)/(-1+i))^{-1} is -1