What is 3i(4-3i)-i(2+i) ?

The solution to 3i(4-3i)-i(2+i) is 10+10i

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simplify 3i(4-3i)-i(2+i)

simplify

3 i (4 - 3 i) - i (2 + i)

10 + 10 i

Solution steps

3 i (4 - 3 i) - i (2 + i)

Expand

3 i (4 - 3 i) : 12 i + 9

= 12 i + 9 - i (2 + i)

Expand

- i (2 + i) : - 2 i + 1

= 12 i + 9 - 2 i + 1

Group like terms

= 12 i - 2 i + 9 + 1

Add similar elements:

12 i - 2 i = 10 i

= 10 i + 9 + 1

Add the numbers:

9 + 1 = 10

= 10 i + 10

Rewrite in standard complex form:

10 + 10 i

= 10 + 10 i

(1 - i) \cdot (1 + i)

3 - \frac{2}{x + 9}

\frac{x + 7}{x + 5} - \frac{7 x}{x ^{2} - 3 x - 40}

(x - 3) (2 x + 1)

\frac{2 x ^{3} + 5 x ^{2} + 9}{x + 3}