What are the solutions to the equation 3x^2-12x+13=0 ?

The solutions to the equation 3x^2-12x+13=0 are x=2+i(sqrt(3))/3 ,x=2-i(sqrt(3))/3

Find the zeros of 3x^2-12x+13=0

The zeros of 3x^2-12x+13=0 are x=2+i(sqrt(3))/3 ,x=2-i(sqrt(3))/3

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3 x^{2} - 12 x + 13 = 0

x = 2 + i \frac{3}{3}, x = 2 - i \frac{3}{3}

Solution steps

3 x^{2} - 12 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 13}{2 \cdot 3}

Simplify

(- 12)^{2} - 4 \cdot 3 \cdot 13 : 23 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 2 3 i}{2 \cdot 3}

x = \frac{- ( - 12 ) + 2 3 i}{2 \cdot 3} : 2 + i \frac{3}{3}

x = \frac{- ( - 12 ) - 2 3 i}{2 \cdot 3} : 2 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = 2 + i \frac{3}{3}, x = 2 - i \frac{3}{3}

12 = 2 + 27 t - 16 t^{2}

5^{2} + b^{2} = 6^{2}

15 x \cdot 25 (8000 - x) = 161000

2 x^{2} - x = 10

What are the solutions to the equation 3x^2-12x+13=0 ?
The solutions to the equation 3x^2-12x+13=0 are x=2+i(sqrt(3))/3 ,x=2-i(sqrt(3))/3
Find the zeros of 3x^2-12x+13=0
The zeros of 3x^2-12x+13=0 are x=2+i(sqrt(3))/3 ,x=2-i(sqrt(3))/3