What is expand (3x-4)(x^2+6x+3) ?

The solution to expand (3x-4)(x^2+6x+3) is 3x^3+14x^2-15x-12

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expand (3x-4)(x^2+6x+3)

expand

(3 x - 4) (x^{2} + 6 x + 3)

3 x^{3} + 14 x^{2} - 15 x - 12

Solution steps

(3 x - 4) (x^{2} + 6 x + 3)

Distribute parentheses

= 3 x x^{2} + 3 x \cdot 6 x + 3 x \cdot 3 - 4 x^{2} - 4 \cdot 6 x - 4 \cdot 3

Simplify

3 x x^{2} + 3 x \cdot 6 x + 3 x \cdot 3 - 4 x^{2} - 4 \cdot 6 x - 4 \cdot 3 : 3 x^{3} + 14 x^{2} - 15 x - 12

= 3 x^{3} + 14 x^{2} - 15 x - 12

\frac{7 ^{5}}{7 ^{2}}

- 2 (8 d + 10 f) - 7 f - 10 (- 7 f + 7 d)

\frac{- 8}{3}

10 \cdot 9 \cdot 8 \cdot 7

lo g_{8} (15)

What is expand (3x-4)(x^2+6x+3) ?
The solution to expand (3x-4)(x^2+6x+3) is 3x^3+14x^2-15x-12