What is (\frac{x^2-1)/(x^2-5x-6)}{(5x+25)/(x-6)} ?

The solution to (\frac{x^2-1)/(x^2-5x-6)}{(5x+25)/(x-6)} is (x-1)/(5x+25)

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simplify (\frac{x^2-1)/(x^2-5x-6)}{(5x+25)/(x-6)}

simplify

\frac{\frac{x ^{2} - 1}{x ^{2} - 5 x - 6}}{\frac{5 x + 25}{x - 6}}

\frac{x - 1}{5 x + 25}

Solution steps

\frac{\frac{x ^{2} - 1}{x ^{2} - 5 x - 6}}{\frac{5 x + 25}{x - 6}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 1 ) ( x - 6 )}{( x ^{2} - 5 x - 6 ) ( 5 x + 25 )}

Cancel

\frac{( x ^{2} - 1 ) ( x - 6 )}{( x ^{2} - 5 x - 6 ) ( 5 x + 25 )} : \frac{x - 1}{5 x + 25}

= \frac{x - 1}{5 x + 25}

\frac{80}{20}

(y + 5)^{2}

\frac{2 x ^{2}}{3 x ^{2} - 4 x}

(- 7 a^{5} c^{2}) (2 a^{4} b c^{6})

(2 x + 1) (3 x - 1)

What is (\frac{x^2-1)/(x^2-5x-6)}{(5x+25)/(x-6)} ?
The solution to (\frac{x^2-1)/(x^2-5x-6)}{(5x+25)/(x-6)} is (x-1)/(5x+25)