What is (2x+4)^2+(2x-4)^2 ?

The solution to (2x+4)^2+(2x-4)^2 is 8x^2+32

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simplify (2x+4)^2+(2x-4)^2

simplify

(2 x + 4)^{2} + (2 x - 4)^{2}

8 x^{2} + 32

Solution steps

(2 x + 4)^{2} + (2 x - 4)^{2}

Expand

(2 x + 4)^{2} : 4 x^{2} + 16 x + 16

= 4 x^{2} + 16 x + 16 + (2 x - 4)^{2}

Expand

(2 x - 4)^{2} : 4 x^{2} - 16 x + 16

= 4 x^{2} + 16 x + 16 + 4 x^{2} - 16 x + 16

Group like terms

= 4 x^{2} + 4 x^{2} + 16 x - 16 x + 16 + 16

Add similar elements:

4 x^{2} + 4 x^{2} = 8 x^{2}

= 8 x^{2} + 16 x - 16 x + 16 + 16

Add similar elements:

16 x - 16 x = 0

= 8 x^{2} + 16 + 16

Add the numbers:

16 + 16 = 32

= 8 x^{2} + 32

lo g_{10} ((\frac{6}{11})^{5})

\frac{1}{2} \div \frac{1}{6}

lo g_{2} (2000)

64 - 121 x^{2}

\frac{3 x + 2}{x - 7} - \frac{2 x}{x ^{2} - 5 x - 14}