What are the solutions to the equation 0=x^2-3x-28 ?

The solutions to the equation 0=x^2-3x-28 are x=7,x=-4

Find the zeros of 0=x^2-3x-28

The zeros of 0=x^2-3x-28 are x=7,x=-4

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0 = x^{2} - 3 x - 28

x = 7, x = - 4

Solution steps

0 = x^{2} - 3 x - 28

Switch sides

x^{2} - 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 1}

x = \frac{- ( - 3 ) + 11}{2 \cdot 1} : 7

x = \frac{- ( - 3 ) - 11}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 7, x = - 4

848 + 75

x^{\frac{5}{2}} - 81 x^{\frac{1}{2}}

235 x^{2} + 0.2756 x + 0.08544 = 0

(x - 6)^{2} = 16

\frac{3 x - 1}{7} - \frac{2 - 4 x}{3} \geq \frac{- 5 - 14}{14} + 7 x + 6

What are the solutions to the equation 0=x^2-3x-28 ?
The solutions to the equation 0=x^2-3x-28 are x=7,x=-4
Find the zeros of 0=x^2-3x-28
The zeros of 0=x^2-3x-28 are x=7,x=-4