What is (x-2+i)(x-2-i) ?

The solution to (x-2+i)(x-2-i) is x^2-4x+5

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simplify (x-2+i)(x-2-i)

simplify

(x - 2 + i) (x - 2 - i)

x^{2} - 4 x + 5

Solution steps

(x - 2 + i) (x - 2 - i)

Rewrite

x - 2 - i

in standard complex form:

(x - 2) - i

= (x - 2 + i) ((x - 2) - i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= (x - 2)^{2} + 1^{2}

Simplify

(x - 2)^{2} + 1^{2} : x^{2} - 4 x + 5

= x^{2} - 4 x + 5

\frac{2}{29}

lo g_{2} (4000)

\frac{20 v ^{9}}{( 4 v ) ^{2}}

\frac{3 x}{2 x - 6} + \frac{9}{6 - 2 x}