What is expand (2x-5)(x^2-3x+4) ?

The solution to expand (2x-5)(x^2-3x+4) is 2x^3-11x^2+23x-20

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expand (2x-5)(x^2-3x+4)

expand

(2 x - 5) (x^{2} - 3 x + 4)

2 x^{3} - 11 x^{2} + 23 x - 20

Solution steps

(2 x - 5) (x^{2} - 3 x + 4)

Distribute parentheses

= 2 x x^{2} + 2 x (- 3 x) + 2 x \cdot 4 - 5 x^{2} - 5 (- 3 x) - 5 \cdot 4

Simplify

2 x x^{2} + 2 x (- 3 x) + 2 x \cdot 4 - 5 x^{2} - 5 (- 3 x) - 5 \cdot 4 : 2 x^{3} - 11 x^{2} + 23 x - 20

= 2 x^{3} - 11 x^{2} + 23 x - 20

4800

\frac{( 32 m ^{5} n ^{6} )}{( 2 m ^{3} n )}

(x + 7) (x + 10)

4 x^{4} + 8 x^{2} y^{2} + 9 y^{4}

\frac{5}{6 x} - \frac{4}{9 x}

What is expand (2x-5)(x^2-3x+4) ?
The solution to expand (2x-5)(x^2-3x+4) is 2x^3-11x^2+23x-20