What is (1+6i)+(6-2i)-(-7+5i) ?

The solution to (1+6i)+(6-2i)-(-7+5i) is 14-i

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simplify (1+6i)+(6-2i)-(-7+5i)

simplify

(1 + 6 i) + (6 - 2 i) - (- 7 + 5 i)

14 - i

Solution steps

(1 + 6 i) + (6 - 2 i) - (- 7 + 5 i)

Simplify

(1 + 6 i) + (6 - 2 i) - (- 7 + 5 i) : 1 + 6 i + 6 - 2 i - (- 7 + 5 i)

= 1 + 6 i + 6 - 2 i - (- 7 + 5 i)

Group like terms

= 6 i - 2 i - (- 7 + 5 i) + 1 + 6

Add similar elements:

6 i - 2 i = 4 i

= 4 i - (- 7 + 5 i) + 1 + 6

Add the numbers:

1 + 6 = 7

= 4 i - (- 7 + 5 i) + 7

Remove parentheses:

- (a + bi) = - a - bi

= 4 i + - (- 7) - 5 i + 7

Apply rule:

a - (- b) = a + b

4 i - (- 7) = 4 i + 7

= 4 i + 7 - 5 i + 7

Group like terms

= 4 i - 5 i + 7 + 7

Add similar elements:

4 i - 5 i = - i

= - i + 7 + 7

Add the numbers:

7 + 7 = 14

= - i + 14

Rewrite in standard complex form:

14 - i

= 14 - i

8 \times 12

81 + - 7 + 9 + - 112

45 \div 15

\frac{7}{2} + \frac{1}{2}

(3 n^{2})^{3}