What is (3x^2+x+1)+(2x^2-3x-5) ?

The solution to (3x^2+x+1)+(2x^2-3x-5) is 5x^2-2x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3x^2+x+1)+(2x^2-3x-5)

simplify

(3 x^{2} + x + 1) + (2 x^{2} - 3 x - 5)

5 x^{2} - 2 x - 4

Solution steps

(3 x^{2} + x + 1) + (2 x^{2} - 3 x - 5)

Simplify

(3 x^{2} + x + 1) + (2 x^{2} - 3 x - 5) : 3 x^{2} + x + 1 + 2 x^{2} - 3 x - 5

= 3 x^{2} + x + 1 + 2 x^{2} - 3 x - 5

Group like terms

= 3 x^{2} + 2 x^{2} + x - 3 x + 1 - 5

Add similar elements:

3 x^{2} + 2 x^{2} = 5 x^{2}

= 5 x^{2} + x - 3 x + 1 - 5

Add similar elements:

x - 3 x = - 2 x

= 5 x^{2} - 2 x + 1 - 5

Subtract the numbers:

1 - 5 = - 4

= 5 x^{2} - 2 x - 4

lo g_{\frac{3}{2}} (\frac{27}{8})

\frac{2}{3} \cdot (- 1)

2 x - 4 x

\frac{( 2 h ^{2} ) ^{3}}{10 h ^{4}}

\frac{1 + 3}{3 - 1}

What is (3x^2+x+1)+(2x^2-3x-5) ?
The solution to (3x^2+x+1)+(2x^2-3x-5) is 5x^2-2x-4