What are the solutions to the equation x^2+(x+2)^2=34 ?

The solutions to the equation x^2+(x+2)^2=34 are x=3,x=-5

Find the zeros of x^2+(x+2)^2=34

The zeros of x^2+(x+2)^2=34 are x=3,x=-5

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x^{2} + (x + 2)^{2} = 34

x = 3, x = - 5

Solution steps

x^{2} + (x + 2)^{2} = 34

Expand

x^{2} + (x + 2)^{2} : 2 x^{2} + 4 x + 4

2 x^{2} + 4 x + 4 = 34

Move

34

to the left side

2 x^{2} + 4 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 30 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 30) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 2}, x_{2} = \frac{- 4 - 16}{2 \cdot 2}

x = \frac{- 4 + 16}{2 \cdot 2} : 3

x = \frac{- 4 - 16}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

7 w + 42 = 133

25 + 144

12 - 2 x \geq 2 x - 4

15 x^{2} + 11 x - 12

∣ x - 1 ∣ = ∣ x ∣ - 1

What are the solutions to the equation x^2+(x+2)^2=34 ?
The solutions to the equation x^2+(x+2)^2=34 are x=3,x=-5
Find the zeros of x^2+(x+2)^2=34
The zeros of x^2+(x+2)^2=34 are x=3,x=-5