What is (x^2-4x+4)/(x^2+5x-14) ?

The solution to (x^2-4x+4)/(x^2+5x-14) is (x-2)/(x+7)

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simplify (x^2-4x+4)/(x^2+5x-14)

simplify

\frac{x ^{2} - 4 x + 4}{x ^{2} + 5 x - 14}

\frac{x - 2}{x + 7}

Solution steps

\frac{x ^{2} - 4 x + 4}{x ^{2} + 5 x - 14}

Factor

x^{2} - 4 x + 4 : (x - 2)^{2}

= \frac{( x - 2 ) ^{2}}{x ^{2} + 5 x - 14}

Factor

x^{2} + 5 x - 14 : (x - 2) (x + 7)

= \frac{( x - 2 ) ^{2}}{( x - 2 ) ( x + 7 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - 2)^{2} = (x - 2) (x - 2)

= \frac{( x - 2 ) ( x - 2 )}{( x - 2 ) ( x + 7 )}

Cancel the common factor:

x - 2

= \frac{x - 2}{x + 7}

(n - 7)^{3}

1200 (\frac{1 g b}{1024 mb})

(6 n + 3) (6 n - 4)

3 \cdot 2 a

\frac{2}{x + 2} + \frac{x}{x + 2}

What is (x^2-4x+4)/(x^2+5x-14) ?
The solution to (x^2-4x+4)/(x^2+5x-14) is (x-2)/(x+7)