What is (2y^2+7y+11)-(8y^2-5y+7) ?

The solution to (2y^2+7y+11)-(8y^2-5y+7) is -6y^2+12y+4

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simplify (2y^2+7y+11)-(8y^2-5y+7)

simplify

(2 y^{2} + 7 y + 11) - (8 y^{2} - 5 y + 7)

- 6 y^{2} + 12 y + 4

Solution steps

(2 y^{2} + 7 y + 11) - (8 y^{2} - 5 y + 7)

Apply rule:

(a) = a

(2 y^{2} + 7 y + 11) = 2 y^{2} + 7 y + 11

= 2 y^{2} + 7 y + 11 - (8 y^{2} - 5 y + 7)

Apply the distributive law:

- (a - b) = - a + b

- (8 y^{2} - 5 y + 7) = - 8 y^{2} + 5 y - 7

= 2 y^{2} + 7 y + 11 - 8 y^{2} + 5 y - 7

Group like terms

= 2 y^{2} - 8 y^{2} + 7 y + 5 y + 11 - 7

Add similar elements:

2 y^{2} - 8 y^{2} = - 6 y^{2}

= - 6 y^{2} + 7 y + 5 y + 11 - 7

Add similar elements:

7 y + 5 y = 12 y

= - 6 y^{2} + 12 y + 11 - 7

Subtract the numbers:

11 - 7 = 4

= - 6 y^{2} + 12 y + 4

(1 - x) (4 - x)

\frac{( - 1 ) ^{3}}{3}

7 \cdot 6 \cdot 5 \cdot 4

x^{3} + x^{2} - 2 x - 2

2 5^{2} - 7^{2}

What is (2y^2+7y+11)-(8y^2-5y+7) ?
The solution to (2y^2+7y+11)-(8y^2-5y+7) is -6y^2+12y+4