What are the solutions to the equation 4n^2-9=0 ?

The solutions to the equation 4n^2-9=0 are n= 3/2 ,n=-3/2

Find the zeros of 4n^2-9=0

The zeros of 4n^2-9=0 are n= 3/2 ,n=-3/2

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4 n^{2} - 9 = 0

n = \frac{3}{2}, n = - \frac{3}{2}

Solution steps

4 n^{2} - 9 = 0

Move

9

to the right side

4 n^{2} = 9

Divide both sides by

4

n^{2} = \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{9}{4}, n = - \frac{9}{4}

\frac{9}{4} = \frac{3}{2}

- \frac{9}{4} = - \frac{3}{2}

n = \frac{3}{2}, n = - \frac{3}{2}

\frac{- ( 1 - 0 ) ^{2}}{2 ( 1 ^{2} )}

\frac{7 ^{2}}{3 ^{2} - 2}

3 z^{2} + z + 3 = 0

\frac{1}{- \frac{1}{2}}

5 x^{2} + 14 x y + 8 y^{2}

What are the solutions to the equation 4n^2-9=0 ?
The solutions to the equation 4n^2-9=0 are n= 3/2 ,n=-3/2
Find the zeros of 4n^2-9=0
The zeros of 4n^2-9=0 are n= 3/2 ,n=-3/2