What is factor 5x^3-9x^2+28x+6 ?

The solution to factor 5x^3-9x^2+28x+6 is (5x+1)(x^2-2x+6)

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factor 5x^3-9x^2+28x+6

factor

5 x^{3} - 9 x^{2} + 28 x + 6

(5 x + 1) (x^{2} - 2 x + 6)

Solution steps

5 x^{3} - 9 x^{2} + 28 x + 6

Use the rational root theorem

a_{0} = 6, a_{n} = 5

The dividers of

a_{0} : 1, 2, 3, 6,

The dividers of

a_{n} : 1, 5

Therefore, check the following rational numbers:

\pm \frac{1 , 2 , 3 , 6}{1 , 5}

- \frac{1}{5}

is a root of the expression, so factor out

5 x + 1

= (5 x + 1) \frac{5 x ^{3} - 9 x ^{2} + 28 x + 6}{5 x + 1}

\frac{5 x ^{3} - 9 x ^{2} + 28 x + 6}{5 x + 1} = x^{2} - 2 x + 6

= (5 x + 1) (x^{2} - 2 x + 6)

(x - 1) (2 x - 1)

\frac{4 x ^{2} - 1}{4 x ^{2} + 4 x + 1}

x (x + 1)^{3}

4 - y^{2}

- 6 x^{4} - 27 x^{3}

What is factor 5x^3-9x^2+28x+6 ?
The solution to factor 5x^3-9x^2+28x+6 is (5x+1)(x^2-2x+6)