What is (3x^3+5x^2-48x-80)/(x+4) ?

The solution to (3x^3+5x^2-48x-80)/(x+4) is (3x+5)(x-4)

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simplify (3x^3+5x^2-48x-80)/(x+4)

simplify

\frac{3 x ^{3} + 5 x ^{2} - 48 x - 80}{x + 4}

(3 x + 5) (x - 4)

Solution steps

\frac{3 x ^{3} + 5 x ^{2} - 48 x - 80}{x + 4}

= \frac{( 3 x ^{3} + 5 x ^{2} ) + ( - 48 x - 80 )}{x + 4}

Factor out

x^{2}

from

3 x^{3} + 5 x^{2} : x^{2} (3 x + 5)

Factor out

- 16

from

- 48 x - 80 : - 16 (3 x + 5)

= \frac{x ^{2} ( 3 x + 5 ) - 16 ( 3 x + 5 )}{x + 4}

Factor out common term

3 x + 5

= \frac{( 3 x + 5 ) ( x ^{2} - 16 )}{x + 4}

Factor

x^{2} - 16 : (x + 4) (x - 4)

= \frac{( 3 x + 5 ) ( x + 4 ) ( x - 4 )}{x + 4}

Cancel the common factor:

x + 4

= (3 x + 5) (x - 4)

(1 + 3 x)^{3}

\frac{4 ( x ^{5} ) ^{3}}{12 x ^{9}}

(3 x - 1) (x - 2)

\frac{10 3}{3}

- 1^{- 3}

What is (3x^3+5x^2-48x-80)/(x+4) ?
The solution to (3x^3+5x^2-48x-80)/(x+4) is (3x+5)(x-4)