What is (3x+24)/(x-1)*(x^2-4)/(x^2+6x-16) ?

The solution to (3x+24)/(x-1)*(x^2-4)/(x^2+6x-16) is (3(x+2))/(x-1)

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simplify (3x+24)/(x-1)*(x^2-4)/(x^2+6x-16)

simplify

\frac{3 x + 24}{x - 1} \cdot \frac{x ^{2} - 4}{x ^{2} + 6 x - 16}

\frac{3 ( x + 2 )}{x - 1}

Solution steps

\frac{3 x + 24}{x - 1} \cdot \frac{x ^{2} - 4}{x ^{2} + 6 x - 16}

Cancel

\frac{x ^{2} - 4}{x ^{2} + 6 x - 16} : \frac{x + 2}{x + 8}

= \frac{3 x + 24}{x - 1} \cdot \frac{x + 2}{x + 8}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 x + 24 ) ( x + 2 )}{( x - 1 ) ( x + 8 )}

Factor

3 x + 24 : 3 (x + 8)

= \frac{3 ( x + 8 ) ( x + 2 )}{( x - 1 ) ( x + 8 )}

Cancel the common factor:

x + 8

= \frac{3 ( x + 2 )}{x - 1}

(2 n^{2} + 5 n + 3) (4 n - 5)

x - 9 + 3 x - x^{2}

1 - \frac{6}{7}

\frac{25 m ^{- 12}}{36 m ^{10}}

\frac{9 ^{8}}{9 ^{6}}

What is (3x+24)/(x-1)*(x^2-4)/(x^2+6x-16) ?
The solution to (3x+24)/(x-1)*(x^2-4)/(x^2+6x-16) is (3(x+2))/(x-1)