What is (\frac{x^2+6x+8)/(x+4)}{(x^2-4)/(4x-8)} ?

The solution to (\frac{x^2+6x+8)/(x+4)}{(x^2-4)/(4x-8)} is 4

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simplify (\frac{x^2+6x+8)/(x+4)}{(x^2-4)/(4x-8)}

simplify

\frac{\frac{x ^{2} + 6 x + 8}{x + 4}}{\frac{x ^{2} - 4}{4 x - 8}}

4

Solution steps

\frac{\frac{x ^{2} + 6 x + 8}{x + 4}}{\frac{x ^{2} - 4}{4 x - 8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + 6 x + 8 ) ( 4 x - 8 )}{( x + 4 ) ( x ^{2} - 4 )}

Cancel

\frac{( x ^{2} + 6 x + 8 ) ( 4 x - 8 )}{( x + 4 ) ( x ^{2} - 4 )} : 4

= 4

\frac{- 2 x}{2}

9 - (- 9)

\frac{x}{x ^{2} + x - 2} - \frac{3}{x ^{2} + 2 x - 3} - \frac{x}{x ^{2} + 5 x + 6}

- 4^{1}

\frac{3}{2} x

What is (\frac{x^2+6x+8)/(x+4)}{(x^2-4)/(4x-8)} ?
The solution to (\frac{x^2+6x+8)/(x+4)}{(x^2-4)/(4x-8)} is 4