What are the solutions to the equation -16t^2+70t-55=0 ?

The solutions to the equation -16t^2+70t-55=0 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)

Find the zeros of -16t^2+70t-55=0

The zeros of -16t^2+70t-55=0 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)

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- 16 t^{2} + 70 t - 55 = 0

t = \frac{35 - 345}{16}, t = \frac{35 + 345}{16}

Solution steps

- 16 t^{2} + 70 t - 55 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 16 ) ( - 55 )}{2 ( - 16 )}

7 0^{2} - 4 (- 16) (- 55) = 2345

t_{1, 2} = \frac{- 70 \pm 2 345}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 70 + 2 345}{2 ( - 16 )}, t_{2} = \frac{- 70 - 2 345}{2 ( - 16 )}

t = \frac{- 70 + 2 345}{2 ( - 16 )} : \frac{35 - 345}{16}

t = \frac{- 70 - 2 345}{2 ( - 16 )} : \frac{35 + 345}{16}

The solutions to the quadratic equation are:

t = \frac{35 - 345}{16}, t = \frac{35 + 345}{16}

4 (2 y + 6) = - 4 y

25 x^{2} = 4

- 2 (x + 4) + 6 = - 3

3 x - 4 > x + 6

\frac{5}{4} + \frac{3 x}{2} = \frac{7 x}{6}

What are the solutions to the equation -16t^2+70t-55=0 ?
The solutions to the equation -16t^2+70t-55=0 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)
Find the zeros of -16t^2+70t-55=0
The zeros of -16t^2+70t-55=0 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)