What is (\frac{x-5)/(x-7)}{(x^2+2x-35)/(x^2-49)} ?

The solution to (\frac{x-5)/(x-7)}{(x^2+2x-35)/(x^2-49)} is 1

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simplify (\frac{x-5)/(x-7)}{(x^2+2x-35)/(x^2-49)}

simplify

\frac{\frac{x - 5}{x - 7}}{\frac{x ^{2} + 2 x - 35}{x ^{2} - 49}}

1

Solution steps

\frac{\frac{x - 5}{x - 7}}{\frac{x ^{2} + 2 x - 35}{x ^{2} - 49}}

Cancel

\frac{x ^{2} + 2 x - 35}{x ^{2} - 49} : \frac{x - 5}{x - 7}

= \frac{\frac{x - 5}{x - 7}}{\frac{x - 5}{x - 7}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

28 \cdot 20

\frac{x + 7}{x + 8} \cdot \frac{x ^{2} + x - 56}{x ^{2} - 49}

e^{\frac{7 ( 5 l n ( x ^{5} ) )}{5}}

(3 + 3) (3 - 3)

x + (- x)

What is (\frac{x-5)/(x-7)}{(x^2+2x-35)/(x^2-49)} ?
The solution to (\frac{x-5)/(x-7)}{(x^2+2x-35)/(x^2-49)} is 1