What is (-4x^8y^4)/(12x^2y) ?

The solution to (-4x^8y^4)/(12x^2y) is -(x^6y^3)/3

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simplify (-4x^8y^4)/(12x^2y)

simplify

\frac{- 4 x ^{8} y ^{4}}{12 x ^{2} y}

- \frac{x ^{6} y ^{3}}{3}

Solution steps

\frac{- 4 x ^{8} y ^{4}}{12 x ^{2} y}

Factor the number:

12 = 4 \cdot 3

= \frac{- 4 x ^{8} y ^{4}}{4 \cdot 3 x ^{2} y}

Cancel the common factor:

4

= \frac{- x ^{8} y ^{4}}{3 x ^{2} y}

Simplify

\frac{x ^{8}}{x ^{2}} : x^{6}

= \frac{- x ^{6} y ^{4}}{3 y}

Simplify

\frac{y ^{4}}{y} : y^{3}

= \frac{- x ^{6} y ^{3}}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{x ^{6} y ^{3}}{3}

\frac{3}{4} + \frac{2}{3} + \frac{1}{2}

(x + 6) (2 x + 4)

(9 x^{3} + y^{2} z) (x^{3} y^{4} z)

\frac{180}{20}

(x - 5) (x - 1) (x + 2)

What is (-4x^8y^4)/(12x^2y) ?
The solution to (-4x^8y^4)/(12x^2y) is -(x^6y^3)/3