What are the solutions to the equation 10^2+12^2=x^2 ?

The solutions to the equation 10^2+12^2=x^2 are x=2sqrt(61),x=-2sqrt(61)

Find the zeros of 10^2+12^2=x^2

The zeros of 10^2+12^2=x^2 are x=2sqrt(61),x=-2sqrt(61)

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1 0^{2} + 1 2^{2} = x^{2}

x = 261, x = - 261

Solution steps

1 0^{2} + 1 2^{2} = x^{2}

Switch sides

x^{2} = 1 0^{2} + 1 2^{2}

Simplify

1 0^{2} + 1 2^{2} : 244

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 244, x = - 244

244 = 261

- 244 = - 261

x = 261, x = - 261

3 w + 4 = 6 w + 19

(\frac{2}{3})^{- 3}

x^{2} > 3 x

\frac{1}{9} + \frac{1}{16}

∣ 4 y + 3 ∣ = 3 ∣ 2 y - 2 ∣

What are the solutions to the equation 10^2+12^2=x^2 ?
The solutions to the equation 10^2+12^2=x^2 are x=2sqrt(61),x=-2sqrt(61)
Find the zeros of 10^2+12^2=x^2
The zeros of 10^2+12^2=x^2 are x=2sqrt(61),x=-2sqrt(61)