What is (\frac{x^2-4)/(x-2)}{(x^2-2x-8)/(3x^3)} ?

The solution to (\frac{x^2-4)/(x-2)}{(x^2-2x-8)/(3x^3)} is (3x^3)/(x-4)

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simplify (\frac{x^2-4)/(x-2)}{(x^2-2x-8)/(3x^3)}

simplify

\frac{\frac{x ^{2} - 4}{x - 2}}{\frac{x ^{2} - 2 x - 8}{3 x ^{3}}}

\frac{3 x ^{3}}{x - 4}

Solution steps

\frac{\frac{x ^{2} - 4}{x - 2}}{\frac{x ^{2} - 2 x - 8}{3 x ^{3}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 4 ) \cdot 3 x ^{3}}{( x - 2 ) ( x ^{2} - 2 x - 8 )}

Cancel

\frac{( x ^{2} - 4 ) \cdot 3 x ^{3}}{( x - 2 ) ( x ^{2} - 2 x - 8 )} : \frac{3 x ^{3}}{x - 4}

= \frac{3 x ^{3}}{x - 4}

k (k + 1) (2 k + 1)

\frac{2}{15}

\frac{x ^{2} - 3 x}{2 x - 6}

1500000 (1 + 0.0287800000000 \dots)^{18}

- 5 + (- 6)

What is (\frac{x^2-4)/(x-2)}{(x^2-2x-8)/(3x^3)} ?
The solution to (\frac{x^2-4)/(x-2)}{(x^2-2x-8)/(3x^3)} is (3x^3)/(x-4)