What is the answer to (3x-2)(2x+1)=6x^2-x-5 ?

The answer to (3x-2)(2x+1)=6x^2-x-5 is No Solution

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(3x-2)(2x+1)=6x^2-x-5

(3 x - 2) (2 x + 1) = 6 x^{2} - x - 5

No Solution

Solution steps

(3 x - 2) (2 x + 1) = 6 x^{2} - x - 5

Expand

(3 x - 2) (2 x + 1) : 6 x^{2} - x - 2

6 x^{2} - x - 2 = 6 x^{2} - x - 5

Move

2

to the right side

6 x^{2} - x = 6 x^{2} - x - 3

Subtract

6 x^{2} - x

from both sides

6 x^{2} - x - (6 x^{2} - x) = 6 x^{2} - x - 3 - (6 x^{2} - x)

Simplify

0 = - 3

The sides are not equal

No Solution

6 x^{2} - 15 x + 6 = 0

\frac{2}{a ^{- 3}}

\frac{2}{3} (x + \frac{1}{2}) = - 1

x^{2} + 2 x = - 7

\frac{2 + 2}{2 - 1}

What is the answer to (3x-2)(2x+1)=6x^2-x-5 ?
The answer to (3x-2)(2x+1)=6x^2-x-5 is No Solution
Solve for x: (3x-2)(2x+1)=6x^2-x-5
The solution is No Solution