What is (3x^3-5x^2-6x+3)-(2x^3+4x-8) ?

The solution to (3x^3-5x^2-6x+3)-(2x^3+4x-8) is x^3-5x^2-10x+11

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simplify (3x^3-5x^2-6x+3)-(2x^3+4x-8)

simplify

(3 x^{3} - 5 x^{2} - 6 x + 3) - (2 x^{3} + 4 x - 8)

x^{3} - 5 x^{2} - 10 x + 11

Solution steps

(3 x^{3} - 5 x^{2} - 6 x + 3) - (2 x^{3} + 4 x - 8)

Apply rule:

(a) = a

(3 x^{3} - 5 x^{2} - 6 x + 3) = 3 x^{3} - 5 x^{2} - 6 x + 3

= 3 x^{3} - 5 x^{2} - 6 x + 3 - (2 x^{3} + 4 x - 8)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{3} + 4 x - 8) = - 2 x^{3} - 4 x + 8

= 3 x^{3} - 5 x^{2} - 6 x + 3 - 2 x^{3} - 4 x + 8

Group like terms

= 3 x^{3} - 2 x^{3} - 5 x^{2} - 6 x - 4 x + 3 + 8

Add similar elements:

3 x^{3} - 2 x^{3} = x^{3}

= x^{3} - 5 x^{2} - 6 x - 4 x + 3 + 8

Add similar elements:

- 6 x - 4 x = - 10 x

= x^{3} - 5 x^{2} - 10 x + 3 + 8

Add the numbers:

3 + 8 = 11

= x^{3} - 5 x^{2} - 10 x + 11

(10 + 7 r - r^{2}) + (- 6 r^{2} - 18 + 5 r)

z + (z + 6)

5 a^{2} - 3 a + 2 - 8 a^{2} - 5 a + 7

- 4 + - 75 - 9 + - 27

\frac{6}{4} - \frac{4}{3}

What is (3x^3-5x^2-6x+3)-(2x^3+4x-8) ?
The solution to (3x^3-5x^2-6x+3)-(2x^3+4x-8) is x^3-5x^2-10x+11