What is (4x^2yz^3)^2(2xy^2z)^2 ?

The solution to (4x^2yz^3)^2(2xy^2z)^2 is 64x^6y^6z^8

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simplify (4x^2yz^3)^2(2xy^2z)^2

simplify

(4 x^{2} y z^{3})^{2} (2 x y^{2} z)^{2}

64 x^{6} y^{6} z^{8}

Solution steps

(4 x^{2} y z^{3})^{2} (2 x y^{2} z)^{2}

Simplify

(4 x^{2} y z^{3})^{2} : 16 x^{4} y^{2} z^{6}

= 16 x^{4} y^{2} z^{6} (2 x y^{2} z)^{2}

Simplify

(2 x y^{2} z)^{2} : 4 x^{2} y^{4} z^{2}

= 16 x^{4} y^{2} z^{6} \cdot 4 x^{2} y^{4} z^{2}

Multiply the numbers:

16 \cdot 4 = 64

= 64 x^{4} y^{2} z^{6} x^{2} y^{4} z^{2}

Simplify

x^{4} x^{2} : x^{6}

= 64 x^{6} y^{2} z^{6} y^{4} z^{2}

Simplify

y^{2} y^{4} : y^{6}

= 64 x^{6} y^{6} z^{6} z^{2}

Simplify

z^{6} z^{2} : z^{8}

= 64 x^{6} y^{6} z^{8}

\frac{3}{2 - 3}

(a^{2})^{4}

\frac{1}{tan ( x ) - sec ( x )} + \frac{1}{tan ( x ) + sec ( x )}

(5 x + 2) (2 x - 3)

1 - e^{0}

What is (4x^2yz^3)^2(2xy^2z)^2 ?
The solution to (4x^2yz^3)^2(2xy^2z)^2 is 64x^6y^6z^8