What is ((2x-7)^2)/(6x)*(3x)/(8x-28) ?

The solution to ((2x-7)^2)/(6x)*(3x)/(8x-28) is (2x-7)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2x-7)^2)/(6x)*(3x)/(8x-28)

simplify

\frac{( 2 x - 7 ) ^{2}}{6 x} \cdot \frac{3 x}{8 x - 28}

\frac{2 x - 7}{8}

Solution steps

\frac{( 2 x - 7 ) ^{2}}{6 x} \cdot \frac{3 x}{8 x - 28}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 2 x - 7 ) ^{2} \cdot 3 x}{6 x ( 8 x - 28 )}

Cancel the common factor:

x

= \frac{( 2 x - 7 ) ^{2} \cdot 3}{6 ( 8 x - 28 )}

Factor the number:

6 = 3 \cdot 2

= \frac{( 2 x - 7 ) ^{2} \cdot 3}{3 \cdot 2 ( 8 x - 28 )}

Cancel the common factor:

3

= \frac{( 2 x - 7 ) ^{2}}{2 ( 8 x - 28 )}

Factor

8 x - 28 : 4 (2 x - 7)

= \frac{( 2 x - 7 ) ^{2}}{2 \cdot 4 ( 2 x - 7 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(2 x - 7)^{2} = (2 x - 7) (2 x - 7)

= \frac{( 2 x - 7 ) ( 2 x - 7 )}{2 \cdot 4 ( 2 x - 7 )}

Cancel the common factor:

2 x - 7

= \frac{2 x - 7}{2 \cdot 4}

Multiply the numbers:

2 \cdot 4 = 8

= \frac{2 x - 7}{8}

\frac{23}{9}

(2 + i) + (2 - 2 i)

1444

(x + 3) (3 x - 1)

\frac{4 a - 1}{b - 2 a} - \frac{2 a}{4 b - 8 a}

What is ((2x-7)^2)/(6x)*(3x)/(8x-28) ?
The solution to ((2x-7)^2)/(6x)*(3x)/(8x-28) is (2x-7)/8