What are the solutions to the equation 18+3x^2-x=0 ?

The solutions to the equation 18+3x^2-x=0 are x= 1/6+i(sqrt(215))/6 ,x= 1/6-i(sqrt(215))/6

Find the zeros of 18+3x^2-x=0

The zeros of 18+3x^2-x=0 are x= 1/6+i(sqrt(215))/6 ,x= 1/6-i(sqrt(215))/6

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18 + 3 x^{2} - x = 0

x = \frac{1}{6} + i \frac{215}{6}, x = \frac{1}{6} - i \frac{215}{6}

Solution steps

18 + 3 x^{2} - x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 18 : 215 i

x_{1, 2} = \frac{- ( - 1 ) \pm 215 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 215 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 215 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 215 i}{2 \cdot 3} : \frac{1}{6} + i \frac{215}{6}

x = \frac{- ( - 1 ) - 215 i}{2 \cdot 3} : \frac{1}{6} - i \frac{215}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{215}{6}, x = \frac{1}{6} - i \frac{215}{6}

1 - \frac{3}{5} (\frac{2}{3} + \frac{1}{2})

2 x^{2} = 7 x - 5

4 n - 1 = 11

\frac{( 0.23094 ) ( 2.2 )}{4.6}

7 96 m^{3}

What are the solutions to the equation 18+3x^2-x=0 ?
The solutions to the equation 18+3x^2-x=0 are x= 1/6+i(sqrt(215))/6 ,x= 1/6-i(sqrt(215))/6
Find the zeros of 18+3x^2-x=0
The zeros of 18+3x^2-x=0 are x= 1/6+i(sqrt(215))/6 ,x= 1/6-i(sqrt(215))/6