What is (2x+14)/(x^2+15x+56)*(x^2+3x-40)/(6x) ?

The solution to (2x+14)/(x^2+15x+56)*(x^2+3x-40)/(6x) is (x-5)/(3x)

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simplify (2x+14)/(x^2+15x+56)*(x^2+3x-40)/(6x)

simplify

\frac{2 x + 14}{x ^{2} + 15 x + 56} \cdot \frac{x ^{2} + 3 x - 40}{6 x}

\frac{x - 5}{3 x}

Solution steps

\frac{2 x + 14}{x ^{2} + 15 x + 56} \cdot \frac{x ^{2} + 3 x - 40}{6 x}

Cancel

\frac{2 x + 14}{x ^{2} + 15 x + 56} : \frac{2}{x + 8}

= \frac{2}{x + 8} \cdot \frac{x ^{2} + 3 x - 40}{6 x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 ( x ^{2} + 3 x - 40 )}{( x + 8 ) \cdot 6 x}

Factor the number:

6 = 2 \cdot 3

= \frac{2 ( x ^{2} + 3 x - 40 )}{( x + 8 ) \cdot 2 \cdot 3 x}

Cancel the common factor:

2

= \frac{x ^{2} + 3 x - 40}{( x + 8 ) \cdot 3 x}

Factor

x^{2} + 3 x - 40 : (x - 5) (x + 8)

= \frac{( x - 5 ) ( x + 8 )}{( x + 8 ) \cdot 3 x}

Cancel the common factor:

x + 8

= \frac{x - 5}{3 x}

\frac{45 a ^{2} b}{30 ab}

10 lo g_{10} (\frac{1}{1 0 ^{- 12}})

\frac{( 4 x ^{2} - 4 ) ( 12 x ^{2} - 6 x - 6 )}{2 x ^{3} - 2}

\frac{15}{90}

\frac{8}{( - 2 )}

What is (2x+14)/(x^2+15x+56)*(x^2+3x-40)/(6x) ?
The solution to (2x+14)/(x^2+15x+56)*(x^2+3x-40)/(6x) is (x-5)/(3x)