What is ((4a^2h^2-8a^3h+3a^4))/((2a^2)) ?

The solution to ((4a^2h^2-8a^3h+3a^4))/((2a^2)) is ((2h-a)(2h-3a))/2

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simplify ((4a^2h^2-8a^3h+3a^4))/((2a^2))

simplify

\frac{( 4 a ^{2} h ^{2} - 8 a ^{3} h + 3 a ^{4} )}{( 2 a ^{2} )}

\frac{( 2 h - a ) ( 2 h - 3 a )}{2}

Solution steps

\frac{4 a ^{2} h ^{2} - 8 a ^{3} h + 3 a ^{4}}{2 a ^{2}}

Factor

4 h^{2} a^{2} - 8 h a^{3} + 3 a^{4} : a^{2} (4 h^{2} - 8 ha + 3 a^{2})

= \frac{a ^{2} ( 4 h ^{2} - 8 ha + 3 a ^{2} )}{2 a ^{2}}

Factor

4 h^{2} - 8 ha + 3 a^{2} : (2 h - a) (2 h - 3 a)

= \frac{a ^{2} ( 2 h - a ) ( 2 h - 3 a )}{2 a ^{2}}

Cancel the common factor:

a^{2}

= \frac{( 2 h - a ) ( 2 h - 3 a )}{2}

(x + 8) (x - 7)

7 \frac{2}{9} + 6 \frac{5}{6}

5 x^{2} + 5 x

\frac{- 3}{8}

(3 + h)^{3}

What is ((4a^2h^2-8a^3h+3a^4))/((2a^2)) ?
The solution to ((4a^2h^2-8a^3h+3a^4))/((2a^2)) is ((2h-a)(2h-3a))/2