What is (2/5)^{-3}(3/7)^{-3} ?

The solution to (2/5)^{-3}(3/7)^{-3} is 42875/216

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simplify (2/5)^{-3}(3/7)^{-3}

simplify

(\frac{2}{5})^{- 3} (\frac{3}{7})^{- 3}

\frac{42875}{216}

Solution steps

(\frac{2}{5})^{- 3} (\frac{3}{7})^{- 3}

(\frac{2}{5})^{- 3} = \frac{125}{8}

= \frac{125}{8} (\frac{3}{7})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{3}{7})^{- 3} = \frac{1}{( \frac{3}{7} ) ^{3}}

= \frac{125}{8} \cdot \frac{1}{( \frac{3}{7} ) ^{3}}

(\frac{3}{7})^{3} = \frac{27}{343}

= \frac{125}{8} \cdot \frac{1}{\frac{27}{343}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{125}{8} \cdot \frac{343}{27}

\frac{125}{8} \cdot \frac{343}{27} = \frac{42875}{216}

= \frac{42875}{216}

\frac{x + 3}{x ^{2} - 4 x + 4} \cdot \frac{x ^{2} - x - 2}{x ^{2} + 4 x + 3}

12 x^{3} - 12 x^{2} - 24 x

r + (- 5 r)

g (4)

g (t)

What is (2/5)^{-3}(3/7)^{-3} ?
The solution to (2/5)^{-3}(3/7)^{-3} is 42875/216