What is (n^2-5n+6)/(n^2-2n-3) ?

The solution to (n^2-5n+6)/(n^2-2n-3) is (n-2)/(n+1)

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simplify (n^2-5n+6)/(n^2-2n-3)

simplify

\frac{n ^{2} - 5 n + 6}{n ^{2} - 2 n - 3}

\frac{n - 2}{n + 1}

Solution steps

\frac{n ^{2} - 5 n + 6}{n ^{2} - 2 n - 3}

Factor

n^{2} - 5 n + 6 : (n - 2) (n - 3)

= \frac{( n - 2 ) ( n - 3 )}{n ^{2} - 2 n - 3}

Factor

n^{2} - 2 n - 3 : (n + 1) (n - 3)

= \frac{( n - 2 ) ( n - 3 )}{( n + 1 ) ( n - 3 )}

Cancel the common factor:

n - 3

= \frac{n - 2}{n + 1}

x^{\frac{- 3}{2}}

cos^{2} (x) cos (x)

3 x^{3} y^{4} (- 14 x^{2} y^{5})

49 - 121 x^{2}

What is (n^2-5n+6)/(n^2-2n-3) ?
The solution to (n^2-5n+6)/(n^2-2n-3) is (n-2)/(n+1)