What is expand (x-4)(2x^3+7x^2-5) ?

The solution to expand (x-4)(2x^3+7x^2-5) is 2x^4-x^3-28x^2-5x+20

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expand (x-4)(2x^3+7x^2-5)

expand

(x - 4) (2 x^{3} + 7 x^{2} - 5)

2 x^{4} - x^{3} - 28 x^{2} - 5 x + 20

Solution steps

(x - 4) (2 x^{3} + 7 x^{2} - 5)

Distribute parentheses

= x \cdot 2 x^{3} + x \cdot 7 x^{2} + x (- 5) - 4 \cdot 2 x^{3} - 4 \cdot 7 x^{2} - 4 (- 5)

Simplify

x \cdot 2 x^{3} + x \cdot 7 x^{2} + x (- 5) - 4 \cdot 2 x^{3} - 4 \cdot 7 x^{2} - 4 (- 5) : 2 x^{4} - x^{3} - 28 x^{2} - 5 x + 20

= 2 x^{4} - x^{3} - 28 x^{2} - 5 x + 20

- \frac{1}{5}

2 \times 8

(a + b)^{1}

8 + 18 - 32

(2 x - 1) (3 x^{2} - 9 x - 4)

What is expand (x-4)(2x^3+7x^2-5) ?
The solution to expand (x-4)(2x^3+7x^2-5) is 2x^4-x^3-28x^2-5x+20