What is (\frac{7x)/(x-8)}{(x^2+4x-32)/(x^2-64)} ?

The solution to (\frac{7x)/(x-8)}{(x^2+4x-32)/(x^2-64)} is (7x)/(x-4)

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simplify (\frac{7x)/(x-8)}{(x^2+4x-32)/(x^2-64)}

simplify

\frac{\frac{7 x}{x - 8}}{\frac{x ^{2} + 4 x - 32}{x ^{2} - 64}}

\frac{7 x}{x - 4}

Solution steps

\frac{\frac{7 x}{x - 8}}{\frac{x ^{2} + 4 x - 32}{x ^{2} - 64}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{7 x ( x ^{2} - 64 )}{( x - 8 ) ( x ^{2} + 4 x - 32 )}

Cancel

\frac{7 x ( x ^{2} - 64 )}{( x - 8 ) ( x ^{2} + 4 x - 32 )} : \frac{7 x}{x - 4}

= \frac{7 x}{x - 4}

(- 9) (- 7 - 100)

6 x^{2} - 6 x

(- 4 q^{3}) (8 q)

(x^{3} y^{3} - 6) (x^{3} y^{3} + 6)

\frac{x ^{4} - x ^{2} - 2 x - 1}{x ^{2} - x - 1}

What is (\frac{7x)/(x-8)}{(x^2+4x-32)/(x^2-64)} ?
The solution to (\frac{7x)/(x-8)}{(x^2+4x-32)/(x^2-64)} is (7x)/(x-4)