What is (x^2+6x)/(x^2+3x-18) ?

The solution to (x^2+6x)/(x^2+3x-18) is x/(x-3)

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simplify (x^2+6x)/(x^2+3x-18)

simplify

\frac{x ^{2} + 6 x}{x ^{2} + 3 x - 18}

\frac{x}{x - 3}

Solution steps

\frac{x ^{2} + 6 x}{x ^{2} + 3 x - 18}

Factor

x^{2} + 6 x : x (x + 6)

= \frac{x ( x + 6 )}{x ^{2} + 3 x - 18}

Factor

x^{2} + 3 x - 18 : (x - 3) (x + 6)

= \frac{x ( x + 6 )}{( x - 3 ) ( x + 6 )}

Cancel the common factor:

x + 6

= \frac{x}{x - 3}

- x - 7 x^{4}

\frac{8}{7 x} + \frac{3}{5 x}

lo g_{4} (127)

\frac{180}{7}

(- 2 x + 3)^{2}