What is expand (x+3)(x-2)(x+1) ?

The solution to expand (x+3)(x-2)(x+1) is x^3+2x^2-5x-6

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expand (x+3)(x-2)(x+1)

expand

(x + 3) (x - 2) (x + 1)

x^{3} + 2 x^{2} - 5 x - 6

Solution steps

(x + 3) (x - 2) (x + 1)

Expand

(x + 3) (x - 2) (x + 1) : (x^{2} + x - 6) (x + 1)

= (x^{2} + x - 6) (x + 1)

Distribute parentheses

= x^{2} x + x^{2} \cdot 1 + xx + x \cdot 1 - 6 x - 6 \cdot 1

Simplify

x^{2} x + x^{2} \cdot 1 + xx + x \cdot 1 - 6 x - 6 \cdot 1 : x^{3} + 2 x^{2} - 5 x - 6

= x^{3} + 2 x^{2} - 5 x - 6

1 6^{6}

\frac{1}{x ^{2} + 2 x - 24} + \frac{2}{x ^{2} - 2 x - 8} - \frac{3}{x ^{2} + 8 x + 12}

50 \div 10

\frac{2}{40}

3 (- 1)^{\frac{2}{3}}

What is expand (x+3)(x-2)(x+1) ?
The solution to expand (x+3)(x-2)(x+1) is x^3+2x^2-5x-6