What are the solutions to the equation a^2-2a-8=0 ?

The solutions to the equation a^2-2a-8=0 are a=4,a=-2

Find the zeros of a^2-2a-8=0

The zeros of a^2-2a-8=0 are a=4,a=-2

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a^{2} - 2 a - 8 = 0

a = 4, a = - 2

Solution steps

a^{2} - 2 a - 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

a_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

a = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

a = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

a = 4, a = - 2

∣ x + 2 ∣ + 2 \geq 6

\frac{1 - a ^{2}}{1 - a}

5 y^{2} + 45 y = 0

6 x - 4 < 2 x or - 2 x \leq - 6

(x - 2) (x + 1) = 4

What are the solutions to the equation a^2-2a-8=0 ?
The solutions to the equation a^2-2a-8=0 are a=4,a=-2
Find the zeros of a^2-2a-8=0
The zeros of a^2-2a-8=0 are a=4,a=-2