What are the solutions to the equation (x+2)(x+3)=0 ?

The solutions to the equation (x+2)(x+3)=0 are x=-2,x=-3

Find the zeros of (x+2)(x+3)=0

The zeros of (x+2)(x+3)=0 are x=-2,x=-3

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(x + 2) (x + 3) = 0

x = - 2, x = - 3

Solution steps

(x + 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

x^{5} - 21 x^{2} + 20 x

12 - 2 ∣ x + 4 ∣ > 6

x^{3} - 12 x^{2} + 47 x - 60

0 = x^{2} - 5 x + 4

8 + 2 t = 4 + 3 t

What are the solutions to the equation (x+2)(x+3)=0 ?
The solutions to the equation (x+2)(x+3)=0 are x=-2,x=-3
Find the zeros of (x+2)(x+3)=0
The zeros of (x+2)(x+3)=0 are x=-2,x=-3