What are the solutions to the equation w^2+3w=40 ?

The solutions to the equation w^2+3w=40 are w=5,w=-8

Find the zeros of w^2+3w=40

The zeros of w^2+3w=40 are w=5,w=-8

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w^{2} + 3 w = 40

w = 5, w = - 8

Solution steps

w^{2} + 3 w = 40

Move

40

to the left side

w^{2} + 3 w - 40 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 40) = 13

w_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 3 + 13}{2 \cdot 1}, w_{2} = \frac{- 3 - 13}{2 \cdot 1}

w = \frac{- 3 + 13}{2 \cdot 1} : 5

w = \frac{- 3 - 13}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

w = 5, w = - 8

6 v^{2} + 42 v + 72

- 7 d^{2} + 2 d + 9 = 0

108

\frac{x ^{- 1}}{x ^{- 2} + y ^{- 6}}

5 x + 5 > 2 x + 2

What are the solutions to the equation w^2+3w=40 ?
The solutions to the equation w^2+3w=40 are w=5,w=-8
Find the zeros of w^2+3w=40
The zeros of w^2+3w=40 are w=5,w=-8