What are the solutions to the equation x^2+6x+5=0 ?

The solutions to the equation x^2+6x+5=0 are x=-1,x=-5

Find the zeros of x^2+6x+5=0

The zeros of x^2+6x+5=0 are x=-1,x=-5

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x^{2} + 6 x + 5 = 0

x = - 1, x = - 5

Solution steps

x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 \cdot 1}, x_{2} = \frac{- 6 - 4}{2 \cdot 1}

x = \frac{- 6 + 4}{2 \cdot 1} : - 1

x = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

- 4 x + 9 \leq - 3 x + 2

70 + x = 180

7 = \frac{x}{11}

\frac{0}{a}

What are the solutions to the equation x^2+6x+5=0 ?
The solutions to the equation x^2+6x+5=0 are x=-1,x=-5
Find the zeros of x^2+6x+5=0
The zeros of x^2+6x+5=0 are x=-1,x=-5